Hi Fabien,
There is no class attribute defined for DocBook's imageobject element, so it is
unlikely that its value would be handled by the stylesheet. Were you thinking of the
role attribute? I see both class and role on imagedata, but since you are asking
about role="histogram", I'll assume you mean to use the role attribute.
Also, I'm not able to duplicate your results of getting the imageobject's
class="imgopen2" to appear on the div element. Are you using a stylesheet
customization that does that?
DocBook XSL has some limited support for propagating a role attribute to a class
attribute, but that is not a universal mechanism, simply because people use role for
many things and would not necessarily want to see its values appear in their HTML
output.
The stylesheets have a general mechanism for customizing a class attribute, but it
does not apply to . That would require customizing a rather large template named
'process.image.attributes' to add a class attribute. But the class customization
mechanism does work for mediaobject, however. For example, if your source has a role
on mediaobject:
<mediaobject role="histogram">
when combined with the following stylesheet customization (remove the d: namespace if
using DocBook 4):
<xsl:template match="d:mediaobject" mode="class.value">
<xsl:choose>
<xsl:when test="@role">
<xsl:value-of select="@role"/>
</xsl:when>
<xsl:otherwise>mediaobject</xsl:otherwise>
</xsl:choose>
</xsl:template>
will result in this output:
and you can use a CSS selector such as:
div.histogram img { }
to apply any CSS styles you need on the img element.
See this reference for more information on using mode="class.value":
http://www.sagehill.net/docbookxsl/UsingCSS.html#CustomClass
Bob Stayton Sagehill Enterprises bobs@sagehill.net
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